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\title{\vspace*{-1.5in}\textbf{Math 2300-007: Quiz 2}}
\date{}
\author{}


\begin{document}
\maketitle
%\underline{Math 1300-400: Quiz 1}
\lhead{Math 2300-007: Calculus II}
\chead{January, 25 2018}
\rhead{Quiz 1}
\vspace{-.5in}
\noindent
{Name: \underline{\phantom{Aalsdkjflaskdjflaskjflksdjflkdsjf}}} \hfill{Score: \underline{\phantom{lksdjflkdsjf}}}
\vskip1cm
\noindent
\begin{enumerate}
%\item (5 points) Compute the following derivatives
%\begin{enumerate}[(a)]
%\item $\displaystyle \frac{d}{dx} \int_3^x \cos(t)\,dt$\vskip2cm
%\item $\displaystyle \frac{d}{dx} \int_0^5 \ln(3t^2 + 1)\,dt$\vskip2cm
%\item $\displaystyle \frac{d}{dx} \int_{x^2}^{\sin{x}}\frac{1}{\sqrt{t^2 +t}}\,dt$\vskip2cm
%\end{enumerate}
\item (2 points) Evaluate the following\\[12pt]
\begin{tabular}{rl@{\hspace{1.5in}}rl}
 (a) & $\displaystyle\arctan(\sqrt{3}) = $ &(c)& $\displaystyle \sin\left(-\frac{3\pi}{2}\right) =$ \\[48pt]
 (b) & $\displaystyle\int x^{-1} + x^{-2}\,dx = $ &(d) & $\displaystyle \frac{1-\cos(2\theta)}{2} = $  \\[48pt]
\end{tabular}
\item \begin{enumerate}[(a)]
\item (2 points) Write down an integral that you can evaluate with integration by parts.\vskip.75in
\item (3 points) Evaluate your integral from part (a).\vskip2in
\end{enumerate}

\item (3 points) Integrate $\displaystyle\int \tan^3(x)\sec^4(x)\,dx$.
$
%\begin{enumerate}[(a)]
%\item $\displaystyle \int \frac{\cos{\theta}}{1 + \sin^2{\theta}}\,d\theta$\vskip6cm
%\item $\displaystyle \int_1^4 \frac{\ln(x)\sqrt{\ln(x) + 1}}{x}\,dx$\vskip6.5cm
%\end{enumerate}

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\end{enumerate}

\end{document}
