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\title{\vspace*{-1.5in}\textbf{\S8.1: Sequence Convergence Activity}\\}
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\maketitle
%\underline{Math 1300-400: Quiz 1}
\lhead{Math 2300-007: Calculus II}
\chead{Feb. 20, 2018}
\rhead{\S8.1: Seq. Conv. Activity}
\vspace{-.5in}
\noindent
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\noindent
\begin{tabular}{l|c}\hline
Sequence & Notes\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{5}{2n+1}$ & \hspace*{5.05in}\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{e^n}{n!}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \sin\left(\frac{1}{n}\right)$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{(-1)^nn}{e^n}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{\sin{n^2}}{\sqrt{n}}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{(-1)^nn^4}{n!}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{n8^n}{3^{2n+1}}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \cos\left(\frac{n}{n^2}\right)$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{\sqrt{n^2+1}}{3n-1}$ &\\\\\hline
\end{tabular}
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\noindent
\begin{tabular}{l|c}\hline
Sequence & Notes\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \left(1+ \frac{1}{n}\right)^n$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{\ln{n}}{\ln\left(n^2\right)}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{3n^3+n}{1-4n^2}$ & \hspace*{5.05in}\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{(-1)^n2^n}{n^4}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{(-1)^nn^2}{n^2+1}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{n}{\ln{n}}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{10^n}{n5^n}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{n^2}{n\ln{n}}$ &\\\\\hline&\\
$\displaystyle \vphantom{\Bigg|} a_n = \frac{e^n}{\sqrt{n}}$ &\\\\\hline
\end{tabular}

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